# np.nan表示該值不是一個數(shù)，比如數(shù)據(jù)中收入,年齡的缺失值
np.nan == np.nan # False

import numpy as np
in_num = np.nan
out_num = np.nan_to_num(in_num)
print("Input Number:",in_num) # Input Number: nan
print("Output Number:",out_num) # Output Number: 0.0

import numpy as np
Infinite_num = np.inf
Negative_Infinity_num = -np.inf
np.nan_to_num(Infinite_num) # 1.7976931348623157e+308
np.nan_to_num(Negative_Infinity_num) # -1.7976931348623157e+308

import numpy as np
data = np.array([np.inf, -np.inf, np.nan, -128, 128])
deal_data = np.nan_to_num(data)

import numpy as np
# 生成一個3行4列的數(shù)組,設(shè)定第1行，第2、3列位置兩個元素為np.nan
arr = np.array([[1,2,3,4],[5,6,np.nan,np.nan],[9,10,11,12]])
 
# 問題:如何將arr中的nan替換為0?
# 方法1
for i in range(arr.shape[1]):
    col = arr[:,i]
    col[np.isnan(col)] = 0
 
# 方法2,調(diào)用np.nan_to_num方法
arr = np.nan_to_num(arr)
 
# 方法3,用np.isnan()做索引，然后替換
# 一個ndarray數(shù)組arr，可以用np.isnan(arr)定位到nan值的位置,
# 再用arr[np.isnan(t1)] = 指定值,將nan替換為指定值
arr[np.isnan(arr)] = 0