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C++?Primer?Plus詳解_C 語言

作者:燦爛千陽?群山回唱 ? 更新時間: 2022-04-26 編程語言

1.各種數據類型的長度

int main(void)
{
	using namespace std;
	int n(3); // C++還可以這么賦值
	int m{6};
	int f = {8};
	int n_int = INT_MAX; //聲明變量同時賦值=初始化
	short n_short = SHRT_MAX;
	long n_long = LONG_MAX;
	long long n_llong = LLONG_MAX;
	cout << "n = " << n << endl;
	cout << "m = " << m << endl;
	cout << "f = " << f << endl;
	cout << "int is " << sizeof(int) << " bytes." << endl;		// sizeof是運算符不是clmits中的函數.INT_MAX是
	cout << "short is " << sizeof n_short << " bytes." << endl; //函數必須帶括號,sizeof(運算符)在這里可以不跟括號,但查看數據類型必須加括號
	cout << "long is " << sizeof n_long << " bytes." << endl;
	cout << "long long is " << sizeof n_llong << " bytes." << endl;
	cout << "Maximum values: " << endl;
	cout << "int: " << n_int << endl;
	cout << "short: " << n_short << endl;
	cout << "long: " << n_long << endl;
	cout << "long long: " << n_llong << endl;
	return 0;
}

2. 無符號數據類型及cout進制顯示

2.1 無符號數據類型及溢出

#include 
#include  //可以查看數據類型最大值最小值
int main(void)
{
	using namespace std;
	short sam = SHRT_MAX;	  //-32768-32767 (16位)   longlong > long(至少32位)> int > short(至少16位)
	unsigned short sue = sam; // 0-65535
	cout << "sam has " << sam << " dolloars and sue has " << sue << " dolloars" << endl;
	cout << "Add 1 dolloars to each account" << endl;
	sam = sam + 1;
	sue = sue + 1;
	cout << "Now sam has " << sam << " dolloars and sue has " << sue << " dolloars" << endl;
	sam = 0;
	sue = 0;
	sam = sam - 1;
	sue = sue - 1;
	cout << "Now sam has " << sam << " dolloars and sue has " << sue << " dolloars" << endl;
	return 0;
}

2.2 cout十六進制顯示

#include 
int main(void)
{
	using namespace std;
	int cheat = 42;	  //十進制
	int waist = 0x42; //十六進制
	int inseam = 042; //八進制
	cout << hex; //修改cout顯示整數的方式
	cout << "cheat = " << cheat << " 42 (in decimal)" << endl;
	cout << "waist = " << waist << " 0x42 (in hexadicimal)" << endl;
	cout << "inseam = " << inseam << " 042 (in octal)" << endl; // cout默認以十進制顯示整數
	return 0;
}

2.3 cout 八進制十進制十六進制顯示?

#include 
int main(void)
{
	using namespace std;
	int cheat = 42;
	int waist = 0x42;
	int inseam = 042;
	cout << "cheat = " << cheat << " 42 (in decimal)" << endl; // cout默認十進制顯示
	cout << hex; //修改cout為十六進制顯示
	cout << "waist = " << waist << " 0x42 (in hexadicimal)" << endl;
	cout << oct; //修改cout為八進制顯示
	cout << "inseam = " << inseam << " 042 (in octal)" << endl;
	return 0;
}

?3.char、ASCII、\n

3.1 char類型

#include 
int main(void)
{
	using namespace std;
	char ch;
	cout << "Enter a character:" << endl;
	cin >> ch;    //cin將鍵盤輸入的M轉換為77
	cout << "Hello, thanks you for the " << ch << " character." << endl; //cout將77轉換為M,cin和cout的行為由變量類型引導
	return 0;
}

3.2 ASCII與char、cout.put()

#include 
int main()
{
	using namespace std;
	char ch = 'M';
	int i = ch;
	cout << "The ASCII code for " << ch << " is " << i << endl;
	cout << "Add one to the character code:" << endl;
	ch = ch + 1; //顯示下一個字符
	i = ch;
	cout << "The ASCII code for " << ch << " is " << i << endl;
	cout << "Displaying char ch using cout.put(ch)" << endl; // iostream類(數據以及操作數據的方法)的對象cin、cout    矩形(對象)平移(方法)
	cout.put(ch); //用對象訪問類里面的操作方法(函數)、
	cout.put('!');
	cout.put('A');
	cout << "Done" << endl;
	return 0;
}

cin與cout的行為由變量引導?

3.3 轉義字符換行

#include 
int main(void)
{
	using namespace std;
	int n = 10;
	cout << "Hello world!" << endl;
	cout << "Good morning!\n";//使用轉義字符換行,顯示字符串這種方法簡單一點,\n是一個字符哦(換行符)
	cout << "What's your name?" << '\n';
	cout << "What's your name?" << "\n";
	cout << "n = " << n << endl;
	cout << "n = " << n << "\n";
	return 0;
}

4.const

#include 
int main()
{
    using namespace std;
    const int toes = 10; //必須在聲明時賦值(之后不準修改)(對const初始化)
    /*const int toes;
    toes = 10;這種是錯誤的*/
    return 0;
}

5.浮點數(整數部分+小數部分)?

#include 
int main()
{
    using namespace std;
    cout.setf(ios_base::fixed, ios_base::floatfield);
    float tub = 10.0 / 3.0;
    const float million = 1.0E6;
    cout << "tub = " << tub << endl;                             // cout默認輸出小數點后六位
    cout << "A million tubs = " << million * tub << endl;        // float精度達不到
    cout << "Ten million tubs = " << 10 * million * tub << endl; // float精度達不到
    double mint = 10.0 / 3.0;
    cout << "A million mint = " << million * mint << endl;
    cout << "Ten million mint = " << 10 * million * mint << endl; // double精度比float高
    return 0;
}

?6. 比較大的浮點數

#include 
int main()
{
    using namespace std;
    float a = 2.34E22; // 2.34e/E+22   2.34*10^22
    float b = a + 1.0;
    cout << "a = " << a << endl;
    cout << "b = " << b << endl;          //a = b
    cout << "b - a = " << b - a << endl; // float位數只有前六位或前七位有效
    return 0;
}

7.float與double的精度

float單精度 至少32位 double雙精度 至少48位

浮點數在內存中如何存儲的? ? ? ? ??int 類型 5 以0101二進制存儲這個好理解

float 8.25 單精度 內存中32位(bit) ? ? ? double 64位 ? ?計算機存浮點數都是以科學計數法的方式存儲的 ? IEEE標準

8.25 科學計數法 8.25 * 10^0 ? ? ? ? ?112.5 ? 科學計數法 ? 1.125 * 10^2 ? ?十進制的科學計數法 ?但是計算機只認識二進制的科學計數法

8.25 二進制的科學計數法(分成整數部分(倒序)+小數部分(正序)) ?1000.01 ? ?轉換為科學計數法 為1.00001*2^3

50.25 整數部分(32+16+2) ? 110010.01 ? ? ? ? 任何一個浮點數二進制科學計數法為 ? ? 1.?????*2^x ? ?整數部分一定為1

符號占1bit ?正數為 0,負數為 1; ? ? ? ? ? ? ? ? ? ?1.00001*2^3 ? ? 指數3表示小數點右移 ? ? ?

0 - 255 ? 中間127 ?0-126(負次冪) 127-255(代表正次冪)

8.25在內存中的表示: 符號位0? ? ? ? ? ?8位指數位 為127+3=130(3次冪) ? ?130 -- 10000010 ? ? ? 0(符號位) ? ?10000010(指數位) ?00001(小數位,23位) 000000000000000000(18個0)

整數部分1位,小數部分23位,共24位(二進制) ? ? 4位對應一個十進制的數 ? ?24/4=6 ? 對應十進制有效位6位 ? 二進制32位 ? 課本56頁

double類型: 十進制13(52/4)位有效位 ? 二進制64位 ? 符號位1 ? ? ?指數位11 ? 小數位 52

11.17? ? 二進制? ? ? ?1011.001010111100001........(小數部分很難取整,無限長 ) ? 而float最多表示32位小數部分, 二進制超過32位就不對了,十進制超過6位就不對了

26.0在內存中如何存儲的??0100000110100000............

11010.00000000............

1.10100.......0 * 2 ^ 4

符號位:0? ??指數位:127 + 4 = 131?二進制:10000011??小數位:010000000000...........

0.75 二進制 0.110000.............

1.10*(2^-1)

符號位:0? ??指數位:127 + (-1)?= 126?二進制:01111110??小數位:1000000000...........

-2.5 二進制 10.1

-1.01*2^1

符號位:1? ??指數位:127 + 1?= 128?二進制:10000000??小數位:0100000000...........

8.float的誤差

/*
 * @Description:
 * @Date: 2022-02-14 13:25:40
 * @LastEditTime: 2022-02-14 13:56:58
 * @FilePath: \C++\第三章\class6\6_1.cpp
 */
// 26.0在內存中如何存儲的? 11010.00000000............ 1.10100.......0 * 2 ^ 4 符號位:0 指數位:127 + 4 = 131 二進制:10000011 小數位:010000000000...........
#include 
int main(void)
{
    using namespace std;
    float hats, heads;
    cout.setf(ios_base::fixed, ios_base::floatfield); //可以強制打印小數點后六位(沒辦法四舍五入),去掉這一句就可以四舍五入,輸出61.42000000.......0可以不顯示
    cout << "Enter a number: "; // 50.25
    cin >> hats;
    cout << "Enter another number: "; // 11.17
    cin >> heads;
    cout << "hats = " << hats << " heads = " << heads << endl;
    cout << "hats + heads = " << hats + heads << endl; // 61.42  的小數部分 0.42 二進制01101...........無限,但是float二進制小數部分只有23位有效,十進制六位61.4199(近似有效)
    cout << "hats - heads = " << hats - heads << endl;
    cout << "hats * heads = " << hats * heads << endl;
    cout << "hats / heads = " << hats / heads << endl; // folat精度不夠,二進制只能顯示小數點后23位,所以不準,去掉setf()可四舍五入
    return 0;
}

注視掉?cout.setf()

解決辦法:用double? ?可顯示二進制小數點后53位,十進制13位,我們用setf()顯示6位顯然也是準確的

9.乘除法

#include 
int main(void)
{
    using namespace std;
    cout.setf(ios_base::fixed, ios_base::floatfield); //顯示小數點后六位
    cout << "Integer division : 9/5 = " << 9 / 5 << endl; //整數相除結果取出整數部分
    cout << "Float division : 9.0/5.0 = " << 9.0 / 5.0 << endl;
    cout << "Mixed division : 9.0/5 = " << 9.0 / 5 << endl; //混合類型
    cout << "Mixed division : 9/5.0 = " << 9 / 5.0 << endl; //混合類型  浮點型精度高于整型,提升精度為浮點型
    cout << "Double division : 1e7 / 9.0 = " << 1e7 / 9.0 << endl;              //都當成double類型來處理(精度高) 一般定義浮點數用double,編譯器默認當成double處理,除非你強制float
    cout << "FLoat constance division : 1e7f / 9.0f = " << 1e7f / 9.0f << endl; //都當成float類型來處理
    return 0;
}

10.求模運算符

#include 
int main(void)
{
    using namespace std;
    const int pounds_per_stone = 14; //聲明整型類型常量   14榜(pounds)=1英石(stone)
    cout << "Enter your weight in pounds: ";
    int lbs;
    cin >> lbs;
    int stone = lbs / pounds_per_stone;
    int pounds = lbs % pounds_per_stone;
    cout << lbs << "pounds = " << stone << " stone, " << pounds << " pounds." << endl;
    return 0;
}

11.數值轉換

#include 
int main(void)
{
    using namespace std;
    cout.setf(ios_base::fixed, ios_base::floatfield);
    float tree = 3;
    int guess(3.9832); // C++特有賦值方式,這里取出小數的整數部分
    int debt = 6.2E22; //超過了整型的取值范圍,結果不確定,對于int(32位 -2^31---2^31-1)太大了
    cout << "tree = " << tree << endl;
    cout << "guess = " << guess << endl;
    cout << "debt = " << debt << endl;
    return 0;
}

12.強制類型轉換?

 
#include 
int main(void)
{
    using namespace std;
    int auks, bats, coots;
    auks = 19.99 + 11.99;            //計算機用double類型相加計算再轉換為整型,結果取整=31
    bats = (int)19.99 + (int)11.99;  // C語言格式
    coots = int(19.99) + int(11.99); // C++語言格式
    cout << "auks = " << auks << endl;
    cout << "bats = " << auks << endl;
    cout << "coots = " << auks << endl;
    char ch = 'Z';
    cout << "The code for " << ch << " is " << int(ch) << endl;
    cout << static_cast(ch) << endl; //強制類型轉換
    return 0;
}

總結

原文鏈接:https://blog.csdn.net/weixin_44726874/article/details/122894286

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