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Spring Data JPA 多表關聯查詢的實現
多表查詢在spring data jpa中有兩種實現方式,第一種是利用hibernate的級聯查詢來實現,第二種是創建一個結果集的接口來接收連表查詢后的結果。第一種方式需要繼承JpaSpecificationExecutor接口,利用Specification 進行復雜查詢,還需要定義好表之間的映射關系,比較復雜。所以這里還是介紹第二種比較簡單的方式。
一對一映射
- 創建實體類:
- UserInfo類
@Entity
@Data
@Table(name="tb_user")
public class UserInfo implements Serializable {
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Long userId;
private String name;
private int age;
private String sex;
private String email;
// 與 Address 的關聯
private Long addressId;
}
- Address類
@Entity
@Data
@Table(name = "tb_address")
public class Address {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long addressId;
private String areaCode;
private String country;
private String province;
private String city;
private String area;
private String detailAddress;
}
- PartViewInfo類(關聯查詢的結果存儲類)
@Data
public class PartViewInfo {
private String name;
private String areaCode;
//滿參構造函數
public PartViewInfo(String name, String areaCode) {
this.name = name;
this.areaCode = areaCode;
}
}
- 持久層:
- AddressRepository接口
public interface AddressRepository extends JpaRepository<Address, Long> {
}
- UserInfoRepository
public interface UserInfoRepository extends JpaRepository<UserInfo, Long> {
@Query("select new com.example.jpatestformanytable.entity.PartViewInfo(u.name, a.areaCode) from UserInfo u, Address a where u.addressId = a.addressId")
public List<PartViewInfo> findViewInfo2();
}
- 測試代碼:
@SpringBootTest
public class sdda {
@Autowired
private UserInfoRepository userInfoRepository;
@Autowired
private AddressRepository addressRepository;
public void init() {
Address addr1 = new Address("027","CN","HuBei", "WuHan","WuChang", "123 street");
Address addr2 = new Address("023","CN","ChongQing", "ChongQing","YuBei", "123 road");
addressRepository.save(addr1);
addressRepository.save(addr2);
UserInfo user1 = new UserInfo("ZS", 21,"Male","123@xx.com", addr1.getAddressId());
UserInfo user2 = new UserInfo("Ww", 25,"Male","234@xx.com", addr2.getAddressId());
userInfoRepository.save(user1);
userInfoRepository.save(user2);
}
public void deleteAll() {
userInfoRepository.deleteAll();
addressRepository.deleteAll();
}
@Test
public void testQuery() {
init();
List<PartViewInfo> partViewInfoList = userInfoRepository.findViewInfo2();
for (PartViewInfo partViewInfo : partViewInfoList) {
System.out.println(partViewInfo);
}
deleteAll();
}
}
- 測試結果:
- 使用到的相關sql語句
Hibernate: insert into tb_address (area, area_code, city, country, detail_address, province) values (?, ?, ?, ?, ?, ?)
Hibernate: insert into tb_address (area, area_code, city, country, detail_address, province) values (?, ?, ?, ?, ?, ?)
Hibernate: insert into tb_user (address_id, age, email, name, sex) values (?, ?, ?, ?, ?)
Hibernate: insert into tb_user (address_id, age, email, name, sex) values (?, ?, ?, ?, ?)
Hibernate: select userinfo0_.name as col_0_0_, address1_.area_code as col_1_0_ from tb_user userinfo0_ cross join tb_address address1_ where userinfo0_.address_id=address1_.address_id
Hibernate: select userinfo0_.user_id as user_id1_1_, userinfo0_.address_id as address_2_1_, userinfo0_.age as age3_1_, userinfo0_.email as email4_1_, userinfo0_.name as name5_1_, userinfo0_.sex as sex6_1_ from tb_user userinfo0_
Hibernate: delete from tb_user where user_id=?
Hibernate: delete from tb_user where user_id=?
Hibernate: select address0_.address_id as address_1_0_, address0_.area as area2_0_, address0_.area_code as area_cod3_0_, address0_.city as city4_0_, address0_.country as country5_0_, address0_.detail_address as detail_a6_0_, address0_.province as province7_0_ from tb_address address0_
Hibernate: delete from tb_address where address_id=?
Hibernate: delete from tb_address where address_id=?
- 得到的結果
PartViewInfo{name='ZS', areaCode='027'}
PartViewInfo{name='Ww', areaCode='023'}
- 易出問題的地方:
- 持久層的sql語句中,定義別名后就要全用別名,否則報錯。
- 結果類中,要自定義一個滿參數的構造函數,不能靠Lombok。
參考
Spring Data JPA 實現多表關聯查詢
原文鏈接:https://blog.csdn.net/weixin_44962400/article/details/125897134
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