s1 = pd.Series([1,2,3,4,np.nan])
s1_max = s1.max()

s1 = pd.Series([1,2,3,4,np.nan])
s1_max = s1.values.max()
>>>nan

s1 = pd.Series([1,2,3,4,5,np.nan])
#速度由快至慢
np.nanmax(s1.values) > np.nanmax(s1) > s1.max()?

#!/usr/bin/env python
# -*- coding:utf-8 -*- 
# Author: Jia ShiLin
 
import numpy as np
 
a = np.arange(9, dtype=float).reshape(3, 3)
a[[[1], [2]]] = np.nan
print(a)
# isnan函數(shù)
print(np.isnan(a))
a[np.isnan(a)] = 0  # 把nan替換成中值或者均值
print(a)
 
print(np.count_nonzero(a))
 
# sum()統(tǒng)計(jì)求和
b = np.arange(12, dtype=int).reshape(2, 6)
print(b)
print(np.sum(b, axis=0))  # 得到結(jié)果和行的形狀一樣
print(np.sum(b, axis=1))
# .mean()
print(b.mean())
print(b.mean(axis=0))
print(b.mean(axis=1))
# np.median()中位數(shù)
print(np.median(b, axis=0))
# .min() .max()
# .ptp()機(jī)值
print(np.ptp(b))
# .std()標(biāo)注差
print(np.std(b, axis=0))